Question

find the area of the trapezium whose height is 13 cm and the parell sides are 18 cm and 11 cm on the length

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Answer 1

Step-by-step explanation:

Formula for finding the area of a trapezium is

(a+b/2)h

where a and b are the parallel sides

Given that,

a=18cm

b=11cm

h=13cm

So area of the trapezium

= (18+11/2)*13

= (29*13/2)

= 377/2

= 188.5 cm^2

Answer 2

S O L U T I O N :

$\underline{\bf{Given\::}}$

• Parallel sides of trapezium = 18 cm & 11 cm.
• Height of trapezium, (h) = 13 cm

$\underline{\bf{Explanation\::}}$

As we know that formula of the trapezium;

$\boxed{\bf{Area = \frac{1}{2} \times (sum\:of\:base) \times height \:\: (sq.unit) }}$

A/q

$\mapsto\tt{Area = \dfrac{1}{2} \times \bigg(18+11\bigg) \times 13}$

$\mapsto\tt{Area = \dfrac{1}{2} \times 29 \times 13}$

$\mapsto\tt{Area = \dfrac{1}{2} \times 337}$

$\mapsto\tt{Area = \cancel{\dfrac{337}{2}}}$

$\mapsto\bf{Area = 188.5\:cm^{2}}$

Thus,

The area of the trapezium will be 188.5 cm² .