Question

find the area of the trapezium whose parallel sides are 14 cm and 10 cm and whose height is 6cm​

Answer 1

Step-by-step explanation:

Formula for area of trapezium is 1/2 x (sum of parallel sides) x height

1/2 x (14+10) x 6 = 72 cm²

Answer 2

Answer:

Area of the Trapezium is 72 cm²

Step-by-step explanation:

Given :

Parallel sides = 14 cm and 10 cm

Height = 6 cm

To find :

Its area

Solution :

$\bigstar \: \boxed{\sf{Area = \frac{1}{2} \times Sum\:of\:Parallel\:Sides \times Height}}$

$\sf{\implies} \: \dfrac{1}{2} \times (14 + 10) \times 6 \\ \\\sf{\implies} \: \dfrac{1}{2} \times 24 \times 6 \\ \\\sf{\implies} \:12 \times 6 \\ \\ \sf{\implies} \:72$

Area = 72 cm²

$\therefore$ Area of the Trapezium is 72 cm²