Question

Find the area of the trapezium whose parallel sides are 14cm and
10cm and whose height is 6cm.​

Answer 1

Answer:

area of trapezium=sum of parallel sides×height/2

=(14+10)×6/2=24×3

=72cm²

Answer 2

The area of the trapezium $=72 cm^{2}$

Step-by-step explanation:

Given,

The parallel sides of the trapezium, a = 14 cm and b = 10cm and

The height of the trapezium, h = 6 cm

To find, the area of the trapezium = ?

We know that,

Area of trapezium $=\dfrac{1}{2} \times (Sum of parallel sides)\times Height$

$=\dfrac{1}{2} \times (a+b)\times h$

$=\dfrac{1}{2} \times (14+10)\times 6cm^{2}$

$=24\times 3 cm^{2}$

$=72 cm^{2}$

Hence, the area of the trapezium $=72 cm^{2}$