Question

Find the area
of the trapezium whose parallel sides are 2.5m and 5m. Height of the trapezium is 3m.​

Answer 1

$\underline{\underline{\huge{\blue{\tt{\textbf Answer :-}}}}}$

Given :

Parallel sides of trapezium are of length 2.5m and 5m.

Height of trapezium is 3m.

To Find :

Area of the trapezium.

Solution :

Area(trapezium) = [½ × (sum of parallel sides) × distance b/w them(height)]

➱ Area(trapezium) = [½ × (2.5 + 5) × 3]

➱ Area(trapezium) = ½ × 7.5 × 3

➱ Area(trapezium) = 22.5 ÷ 2

➱ Area(trapezium) = 11.25

∴ Area of trapezium is 11.25m²

Answer 2

Answer:

Hence, value of area of the trapezium will be 11.25 sq. m

Step-by-step explanation:

In context to question asked,

We have to determine the one parallel side of trapezium

As per question,

It is given that,

Parallel sides of trapezium = 2.5 m and 5 m

Height of trapezium = 3 m

Sum of parallel sides will be 2.5 + 5 = 7.5 m

As we know that,

Area of trapezium

$A = \frac{a+b}{2}\times h\\Where,\:A = Area\\a,b = Parallel\:sides\:of\:trapezium\\h =Height$

So, for determining the value of area of trapezium we will put the value given in question in above formula,

Thus we will get,

$A = \frac{a+b}{2}\times h\\A = \frac{2.5+5}{2}\times 3\\=>A = \frac{7.5}{2}\times 3\\=>A = \frac{22.5}{2} = 11.25\:m^2$