Question

Find the area of the trapezium, whose parallel sides are 3cm and 7cm and height between them is 4 cm.Required to answer. Single choice.



40 sq cm

20 sq cm

25 sq cm

80 sq cm


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Answer 1

☆ Solution ☆

Given :-

• Sides are 3 cm and 7 cm.
• Height between them is 4 cm.

To Find :-

• The area of trapezium.

Step-by-Step-Explaination :-

As we know that :-

Area of trapezium = 1/2 × sum of parallel sides × height

Putting the respective value,

Area of trapezium = 1/2 × ( 3 + 7 ) × 4

Area of trapezium = 1/2 × 10 × 4

Area of trapezium = 5 × 4

Area of trapezium = 20

Therefore,

The area of trapezium is 20 cm².

Hence,

Option b) 20 cm² is correct option.

Answer 2

Given :-

• Sides = 3 cm & 7 cm.
• Height between them = 4 cm.

To Find :-

• Area of trapezium.

As we know that :-

Area of trapezium = $\sf\dfrac{1}{2}$ × sum of parallel sides × height

Putting the respective value,

Area of trapezium = 1/2 × ( 3 + 7 ) × 4

= 1/2 × 10 × 4

= 5 × 4

= 20

Therefore,

Area of the trapezium is 20 cm².

Hence,

Option b) 20 cm² is correct answer.

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More to know:-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$⠀

$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$⠀

$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$⠀

$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$⠀

$\sf{Perimeter\;of\; Square\;=\;4\;\times\;(Side)}$⠀

$\sf{Perimeter\;of\;Circle\;=\:2\pi r}$

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