Question

Find the area of the trapezium whose parallel sides are 42 cm and 20 cm and the distance between them is 10 cm. *


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Answer 1

Answer:

$200cm^{2}$

Step-by-step explanation:

area of parallelogram= h × b

                                   = 10cm × 20cm

                                   = $200cm^{2}$

Answer 2

• GIVEN:-

Parallel sides of the trapezium are 42 cm and 20 cm.

Distance between them is 10 cm.

• To Find:-

Area of the trapezium.

• SOLUTION:-

Formula of area of trapezium,

$\large\boxed{\sf{\blue{Area = \frac{1}{2}\times(sum \:of \:parallel \:sides)\times(distance \:between\: them) }}}$

According to the question,

$\large\Longrightarrow{\sf{\frac{1}{2}\times(42+20) \times\:10}}$

$\large\Longrightarrow{\sf{\frac{1}{2}\times62 \times\:10}}$

$\large\Longrightarrow{\sf{62 \times5}}$

$\large\Longrightarrow{\sf{310}}$

$\large\red\therefore\boxed{\sf{\red{Area \:of\: trapezium = 310\:{cm}^{2}}}}$