find the area of the trapezium whose parallel sides are 45 cm and 37 cm and the distance between them is 20 CM
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6
by using coordinate geometry method add are of two triangles
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25
area of a trapezium =1/2h(a+b)
a=45cm b=37 cm h=20 cm
1/2×20(45+37)=
10×82=820cm^2 is the answer
a=45cm b=37 cm h=20 cm
1/2×20(45+37)=
10×82=820cm^2 is the answer
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