Question

Find the area of the trapezium whose parallel sides are 6.6 cm and 12.4cm and height is 6cm.​

Answer 1

Step-by-step explanation:

Answer:

4800 cm and 5600 cm

Step-by-step explanation:

Let the parallel sides of a trapezium be 6x and 7x respectively.

Area of trapezium = 6.50 m² = 65000 cm²

According to the question ;

Area of trapezium = \frac{1}{2}

2

1

* (sum of || sides ) * h

⇒ Area of trapezium = \frac{1}{2}

2

1

* (6x + 7x) * 12.5

⇒ 65000 cm² = 12.5 ( 13x ) / 2

⇒ 12.5 * 13x = 65000 * 2

⇒ 13x = 130,000 / 12.5

⇒ 13x = 10,400

⇒ x = 10,400 / 13

⇒ x = 800

Therefore, parallel sides are ;

6x = 6 * 800 = 4800 cm

7x = 7 * 800 = 5600 cm

Answer 2

Let one of the parallel side be P1

And the other be P2

Let height be h

h=6cm

P1=6.6cm

P2=12.4cm

Area of trapezium- 1/2 × sum of parallel sides × height

→Area=1/2× (6.6+12.4) ×6

→1/2×19×6

→19×3

$\huge\fcolorbox{red}{aqua}{57 }$

57cm²

I hope it helps ✌.