Question

find the area of the trepizum given below? ​

Answer 1

Answer:

lol it is not trapezium ok

Answer 2

Answer:

Given

AB = 8 + 6 = 14cm

CD = 8cm

and

$oc = \sqrt{cb {}^{2} - ob {}^{2} } \\ oc = \sqrt{17 {}^{2} - 8 {}^{2} } \\ oc = \sqrt{289 - 64} \\ oc = \sqrt{225} \\ oc = 15cm$

Now area of trapezium = (sum of parallel sides X height) /2

So area if given trapezium

$\frac{(ab + cd) \times oc}{2} \\ =\frac{(14 + 8) \times 15}{2} \\ = \frac{22 \times 15}{2} \\ = 11 \times 15 \\ = 165cm {}^{2}$