Question

find the area of the triangle ABC as shown in figure ​

Answer 1

Hope it helps.. ............. ........

Answer 2

The area of the triangle ΔABC is 120 cm².

Step-by-step explanation:

• ΔABC is a right angle triangle.

        Where

        Hypotenuse (AC) = 26 cm

        AB = 10 cm

• From Pythagoras' rule

        $\mathbf{AC^{2}=AB^{2}+BC^{2}}$

        $\mathbf{26^{2}=10^{2}+BC^{2}}$

        $\mathbf{676=100+BC^{2}}$

        $\mathbf{BC^{2}=676-100}$

        $\mathbf{BC^{2}=576}$

        $\mathbf{BC^{2}=24^2}$

        So

• BC =24 cm

        $\mathbf{\textrm{Area of triangle} \Delta ABC=\frac{1}{2}\times AB\times BC}$

        $\mathbf{\textrm{Area of triangle}\Delta ABC=\frac{1}{2}\times 10\times 24}$

        $\mathbf{\textrm{Area of triangle}\Delta ABC=120 \ cm^2}$