find the area of the triangle ABC, if coordinates of vertices are A(2,0), B(11,6) and C(-4,-4)
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Answered by
15
1/2(2 (6+4)+11 (-4-0)+(-4)(0-6))
1/2(20-44+24)
1/2*0
0
1/2(20-44+24)
1/2*0
0
Abhishek2004:
it is correct right?
Answered by
3
1/2(2 (6+4)+11 (-4-0)+(-4)(0-6))
1/2(20-44+24)
1/2*0
0
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