Question

Find the area of the triangle ABC if the vertices are A(-1,2) B(2,5) C(4,-1)​

Answer 1

Answer:

s=a+b+c/2

  3+3+5/2=11/2

area=√s×(s-a)×(s-b)×(s-c)

        √11/2×5/2×5/2×1/2

        25/4√11

Answer 2

Answer:

area of triangle=12

Step-by-step explanation:

ar of triangle=1/2(x1(y3-y2)+x2(y2-y1)+x3(y1-y3))

1/2(-1(-1-5)+2(5-2)+4(2+1))

1/2(-1(-6)+2(3)+4(3))

1/2(6+6+12)

1/2(12+12)

1/2(24)

1/2*24

24/2

12

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