Question

Find the area of the triangle ABC in which AB = AC = 4 cm and angle A = 90 degree
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Answer 1

Answer:

Step-by-step explanation:

Let AB be base, AC be height.

b=4cm h=4cm

Area of ∆ABC =1/2×b×h sq.units

1/2 ×4×4= 1/2×16 =8 cm^2

Answer 2

Answer:

AREA OF THE TRIANGLE=4

Step-by-step explanation0:

First we'll find hypotenous:-

=AB^2+AC^2=BC^2

=32=BC^2

=_/32=4_/2

semiperimetre=a+b+c/2

                        =6_/2

heron's formula=_/(s-a)(s-b)(s-c)

                         =_/(6_/2-4)(6_/2-4)(6_/2-4_/2)

                          =_/(2_/2*2_/2*2)

                           =_/16

                            =4

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