Question

Find the area of the triangle ABC whose vertices A (-5, -1); B (3,-5) and C (5.2)​

Answer 1

32 square units.

Step-by-step explanation:

The three vertices of the triangle ABC are A(-5,-1), B(3,-5) and C(5,2).

So, the area of the triangle will be

$\frac{1}{2}|-5(- 5 - 2) + 3(2 + 1) + 5(- 1 + 5)| = 32$ sq. units. (Answer)

Note :

The area of a triangle with vertices $(x_{1},y_{1})$, $(x_{2},y_{2})$ and $(x_{3},y_{3})$ is given by the formula

Δ = $\frac{1}{2}|x_{1}(y_{2} - y_{3}) + x_{2}(y_{3} - y_{1}) + x_{3}(y_{1} - y_{2}) |$ sq. units.

Answer 2

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