Question

find the area of the triangle by the points (0,0),(4,0). and (0-3/2)​

Answer 1

Answer:

Hey!!

Here is your answer...

Area of triangle=

1/2|x1(y2-y3)+x2 (y3-y1)+x3(y1-y2)|

Here x1= 0,x2= 4,x3= 0

Y1= 0,y2= 0,y3= -3/2

∆ =1/2 | 0(0-(-3/2)+ 4(-3/2-0)+0(0-0)|

= 1/2|0+(-12/2)+0|

= 1/2|-6|

= 6/2

= 3 sq. Units....

:. Area of triangle = 3 sq. Units...

Hope it helps...

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