Question

find the area of the triangle FAR whose vertices are F (-3,-3),A(2,1) and R(3,4)​

Answer 1

Step-by-step explanation:

using distance formula

distance (F,A) = √{2-(-3)}sq + {(1-(-3)} sq

= √(2+3) sq + (1+3) sq

= √5 sq + 3 sq

= √ 25+9

= √36

= 6 units

Distance (A,R) = √(3-2) sq + (4-1) sq

= √1 sq + 3sq

= √1+9

= √10 units

Distance (R,F) = √(-3-3) sq + (-3-4) sq

= √-6 sq + -7 sq

= √36 + 49

= √85 units

PERIMETRE = 6+√10+√85

= 18.38 units

bro I am telling perimeter because area part is deleted from syllabus.

Answer 2

Answer:

Step-by-step explanation:

Solution is in the attachment