Find the area of the triangle field whose sides are 50 cm 45 cm 35 cm
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Answered by
2
Heya !!
Let A = 50 cm , B = 45 cm and C = 35 cm.
Semi perimeter ( S ) = 1/2 × ( A + B + C )
=> 1/2 × ( 50 + 45 + 35 )
=> 1/2 × 130
=> 65 cm
( S - A ) = 65 - 50 = 15 cm
( S - B ) = 65 - 45 = 20 cm
And,
( S - C ) = 65 - 35 = 30 cm
Therefore,
Area of triangle = ✓S ( S - A )(S -B)(S - C)
=> ✓65 × 15 × 20 × 30
=> ✓585000 cm²
=> ✓ 2 × 2 × 2 × 5 × 5 × 5 × 5 × 3 × 3 × 13
=> 2 × 5 × 5 × 3 ✓ 2 × 13
=> 150✓26 cm².
Let A = 50 cm , B = 45 cm and C = 35 cm.
Semi perimeter ( S ) = 1/2 × ( A + B + C )
=> 1/2 × ( 50 + 45 + 35 )
=> 1/2 × 130
=> 65 cm
( S - A ) = 65 - 50 = 15 cm
( S - B ) = 65 - 45 = 20 cm
And,
( S - C ) = 65 - 35 = 30 cm
Therefore,
Area of triangle = ✓S ( S - A )(S -B)(S - C)
=> ✓65 × 15 × 20 × 30
=> ✓585000 cm²
=> ✓ 2 × 2 × 2 × 5 × 5 × 5 × 5 × 3 × 3 × 13
=> 2 × 5 × 5 × 3 ✓ 2 × 13
=> 150✓26 cm².
Answered by
43
Here is your solution
Given:-
Sides Of a Triangular Field are 50 , 45, 35, metre.
Let,
First Side = a
Second Side = b
Third Side = c
We know that
Semiperimeter = a+b+c/2
=> 50+45+35/2
=> 50+80/2
=> 130/2
=> 65
Hence semiperimeter is 65
Using Heron's Formula
Area = √s(s-a)(s-b)(s-c)
=> √65(65-50)(65-45)(65-35)
=> √65(15)(20)(30)
=> √ 585000
=> 764.85 m²
Now, we have to find
Required number of flower beds that can be prepared if each bed measures 5m²
=> 764.85m² /5m²
=> 152.97
153(approx)
Hence,
Required Number of flower beds = 153
Hope it helps you
Given:-
Sides Of a Triangular Field are 50 , 45, 35, metre.
Let,
First Side = a
Second Side = b
Third Side = c
We know that
Semiperimeter = a+b+c/2
=> 50+45+35/2
=> 50+80/2
=> 130/2
=> 65
Hence semiperimeter is 65
Using Heron's Formula
Area = √s(s-a)(s-b)(s-c)
=> √65(65-50)(65-45)(65-35)
=> √65(15)(20)(30)
=> √ 585000
=> 764.85 m²
Now, we have to find
Required number of flower beds that can be prepared if each bed measures 5m²
=> 764.85m² /5m²
=> 152.97
153(approx)
Hence,
Required Number of flower beds = 153
Hope it helps you
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