find the area of the triangle formed by points (0,0);(4,0);(4,3) by using herons formula
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Answer:
A = 1/2[ x₁(y₂-y₃) + x₂(y₃-y₁)+x₃(y₁-y₂) ]
x₁ = 0 y₁ = 0 x₂ = 4 y₂ = 0 x₃ = 4 y₃ = 3
A = 1/2 [ 0(0-3) + 4(3-0) + 4(0-0) ]
A = 1/2 [ 0 + 12 + 0 ]
A = 1/2*12
A = 6 sq units
Area using heron's formula
two sides are 4 and 3 units therefore third side is 5 units Pythagorean triplet
s = (3+4+5)/2 = 6 [ s = semi perimeter ]
A = √s(s-a)(s-b)(s-c) [ Heron's formula ]
=> √6(6-5)(6-4)(6-3)
=> √6×1×2×3
=> √36
=> 6 sq units
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