Question

Find the area of the triangle formed by the following straight lines and the coordinates axis 1)x-4y+2=0
2)3x-4y+12=0

Answer 1

Answer:

6 sq units

Step-by-step explanation:

First let us find the co ordinates where the line cuts x-axis and y-axis

Put y=0 in the equation 3x-4y=-12 we get 3x=-12 , x=-4

The point where it cuts the x-axis is (-4,0)[let the point be A]

Put x=0 in the equation 3x-4y=-12 we get -4y=-12 y=3

The point where it cuts the y-axis is (0,3) [let the point be B]

Third point is O(0,0)

Area of the Δ AOB=1/2 x b x h =1/2 x -4 x 3=-6 sq units

Since the area should not be negative

Answer =6 sq units

Answer 2

Answer:

Find the area of the triangle formed by the following straight lines and the coordinates axis 1)x-4y+2=0

2)3x-4y+12=0

Step-by-step explanation:

Find the area of the triangle formed by the following straight lines and the coordinates axis 1)x-4y+2=0

2)3x-4y+12=0