Question

Find the area of the triangle formed by the line x + 2y + 1 = 0 with coordinate axes.​

Answer 1

3x+2×0=6 => x=2, A( 2 , 0)

Point of intersection of eq.(2) &(3) is O(0 , 0 )

Point of intersection of eq.(1) & (3) is B , put x=0 in eq. (1)

3×0+2y=6 => y=3 , B(0 ,3 )

Area of triangle AOB=1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)].

=1/2[2(0–3)+0(3–0)+0(0–0)]sq.unit

=1/2(-6)sq.unit

=-3 sq.unit

=3 sq.unit.Answer.