find the area of the triangle formed by the lines 2 X + Y= 6 and 2 x - y + 2 =0 with the x axis. *
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1)2x+y=6
⟹y=6−2x
Let, x=1, then y=6−2(1)=4
Similarly, when x=2,y=2
x−2y+2=0
⟹x=2y−2
Let, y=0, then x=2(0)−2=−2
Similarly, when y=2,x=2
Plotting the above points on the graph, we get, the vertices of the traingle, i.e. A(2,3),B(3,0),C(−2,0)
∴ Area of the triangle =
2
1
×5units×2units
=5 sq. units
2)According to the question, the graph of the line would be;
On solving, we get point as (1,4).
ar(△DOC)=
2
1
(OD)(OC)=
2
1
×1×2=1sq.units
ar(△AOB)=
2
1
(OB)(OA)=
2
1
×3×6=9sq.units
∴ Ratio of areas = 1:9
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