Question

Find the area of the triangle formed by the lines 4x + y - 16 = 0, x - y + 1 = 0
and x - 6y - 4 = 0.
Prove that the line​

Answer 1

Answer:

We have,

x+y=1......(1)

2x+3y=6......(2)

4x−y=−4......(3)

From equation (1) and (2) to and we get,

(x+y=1)×2

2x+3y=6

2x+2y=2

2x+3y=6

On subtracting and we get,

y=4 put in (1) and we get,

2x+2y=2

2x+2(4)=2

2x+8=2

2x=−6

x=−3

Then, (x1,y1)=(−3,4)

From equation (2) and (3) to, and we get

(2x+3y=6)×2

4x−y=−4

4x+6y=12

4x−y=−4

On subtracting and we get,

7y=16

y=716

Put the value of y in equation (2) and we get,

2x+3y=6

2x+3×716=6

2x+748=6

2x=6−