find the area of the triangle formed by the mid point , whose vertices are (2,1) (-2,3) (4,-3)
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The formula of the area of the triangle is 1/2[
2(3+3)-2(-3-1)+4(1-3)]=6square unit
2(3+3)-2(-3-1)+4(1-3)]=6square unit
Feduzz:
is there any kind of squaring any of the terms??
no
thanks
is it herone's formula
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