find the area of the triangle formed by the point (2,3) , (-1,0) ,(2,-4)
Answers
Answer:
hello,here is your answer
Step-by-step explanation:
We are given A(2,3) , B(−1,0) , C(2.−4)
If you have a good-enough visual imagination (or if you draw a sketch) you’ll realize that the triangle aligns nicely with the axes. (The A and C vertices have the same x-coordinate, making one side vertical; and the B coordinate is on the x-axis) So we have two right-angles triangles glued together. One with area 12×3×3=4.5 and the other with area 12×3×4=6 . So the area is 10.5 .
If you can’t visualize, and have no pencil, or are devoted to algebra, then you can use Heron’s Method…
|AB|=32+32−−−−−−√=18−−√
|BC|=32+42−−−−−−√=5
|AC|=02+72−−−−−−√=7
So the semi-perimeter is s=7+5+18√2=8.121320344
Area=s(s−5)(s−7)(s−18−−√)−−−−−−−−−−−−−−−−−−−−−√=10.5
Answer:
Step-by-step explanation:
If you have a good-enough visual imagination (or if you draw a sketch) you’ll realize that the triangle aligns nicely with the axes. (The A and C vertices have the same x-coordinate, making one side vertical; and the B coordinate is on the x-axis) So we have two right-angles triangles glued together. One with area 12×3×3=4.5 and the other with area 12×3×4=6. So the area is 10.5.
If you can’t visualize, and have no pencil, or are devoted to algebra, then you can use Heron’s Method…
|AB|=32+32−−−−−−√=18−−√
|BC|=32+42−−−−−−√=5
|AC|=02+72−−−−−−√=7
So the semi-perimeter is s=7+5+18√2=8.121320344