Question

find the area of the triangle formed by the points (2 3) (-1, 0) and (2 -4) 10th​

Answer 1

Answer:

Step-by-step explanation:

The given points are (2,3),(-1,0),(2,-4)

Area of a triangle

=1/2|[2(0+4)+(-1)(-4-3)+2(3-0)]|

=1/2|[2×4+(-1)(-7)+2×3]

=1/2(8+7+6)

=1/2(21)=10.5 sq. unit.

Hope it will help you.

Answer 2

SOLUTION:-

$\bf\underline{\underline{\red{Question:-}}}$

⠀⠀⠀⠀⠀• Find the area of the triangle formed by ⠀⠀⠀⠀⠀the points (2 3) (-1, 0) and (2 -4)

$\bf\underline{\underline{\blue{Answer:-}}}$

⠀⠀⠀⠀⠀• Area = 10.5 sq. units

$\bf\underline{\underline{\red{Given:-}}}$

⠀⠀⠀⠀⠀• A(2,3)

⠀⠀⠀⠀⠀• B(-1,0)

⠀⠀⠀⠀⠀• C(2,-4)

$\bf\underline{\underline{\blue{To\:Calculate:-}}}$

⠀⠀⠀⠀⠀• Area of Triangle

$\bf\underline{\underline{\red{Explanation:-}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀Using Formula

⠀⠀⠀⠀⇝ 1/2|x1(y2-y3)+x(y3-y1)+x3(y1-y2)|

The Coordinators of the vertices of the Given Triangle are

⠀⠀⠀⠀⠀• A(2,3) = x1,y1

⠀⠀⠀⠀⠀• B(-1,0) = x2,y2

⠀⠀⠀⠀⠀• C(2,-4) = x3,y3

Area ⇝ 1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|

putting values,

➺ 1/2 | 2(0-(-4))+(-1)(-4-3)+2(3-0)|

➺1/2| 2(0+4)-1(-7)+2(3)

➺ 1/2| 2×4-1×-7+2×3

➺1/2|8+7+6|

➺ 1/2| 21

➺ 21/2

⇝ Area = 10.5

$\bf\underline{\underline{\red{Hence:-}}}$

⠀⠀⠀⠀⠀• Area = 10.5 sq. units

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