Question

Find the area of the triangle formed by the points P(2, 3) Q (1-0) and R(2,-4)
​

Answer 1

Answer: the area of the triangle is 7/2(3.5)

Step-by-step explanation:

We know that area of triangle is found with the formula:

1/2[X1(y2-y3)+X2(y3-y1)+x3(y1-y2)]

Now according to the question, X1=2, X2=1, x3=2 and y1=3, y2=0, y3= -4. Now substituting the values in the equation, u get the solution as 7/2(3.5)

Hope this was useful

Answer 2

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Area\:of\:triangle=3.5\:unit^{2}}}$

${\bold{\underline{\underline{Step-by-step\:explanation}}}}$

$\underline \bold{Given : } \\ \implies Coordinate \: of \: P = (2,3) \\ \\ \implies Coordinate \: of \:Q= (1,0) \\ \\ \implies Coordinate \: of \: R = (2,- 4) \\ \\ \underline \bold{To \: Find : } \\ \implies Area \: of \: triangle =?$

• According to given question :

$\bold{Using \: formula \: of \: area \: of \: triangle \: in \: coordinate \: geometry: } \\ \implies Area \: of \: triangle = \frac{1}{2} [ x_{1}(y_{2} - y_{3}) + x_{2}(y_{3} - y_{1}) + x_{3}(y_{1} - y_{2})] \\ \\ \implies Area = \frac{1}{2} [2(0 + 4) + 1( - 4 - 3) + 2(3 - 0) ]\\ \\ \implies Area = \frac{1}{2} [2 \times 4 + 1 \times - 7 + 2 \times 3] \\ \\ \implies Area = \frac{1}{2} [8 - 7 + 6] \\ \\ \implies Area = \frac{1}{2} \times 7 \\ \\ \bold{\implies Area = 3.5 \:unit^{2} }$