Question

Find the area of the triangle
Formed by the points
R (4,-3), s(2,5) , and T(-3 ,4)
​

Answer 1

Answer

AnswerGiven data :- 

AnswerGiven data :- P(−5,7)≡(x1,y1)

AnswerGiven data :- P(−5,7)≡(x1,y1)Q(−4,−5)≡(x2,y2)

AnswerGiven data :- P(−5,7)≡(x1,y1)Q(−4,−5)≡(x2,y2)R(4,5)≡(x3,y3)

AnswerGiven data :- P(−5,7)≡(x1,y1)Q(−4,−5)≡(x2,y2)R(4,5)≡(x3,y3)To find :- Area of triangle PQR

AnswerGiven data :- P(−5,7)≡(x1,y1)Q(−4,−5)≡(x2,y2)R(4,5)≡(x3,y3)To find :- Area of triangle PQRSolution :-

AnswerGiven data :- P(−5,7)≡(x1,y1)Q(−4,−5)≡(x2,y2)R(4,5)≡(x3,y3)To find :- Area of triangle PQRSolution :-Ref. image

AnswerGiven data :- P(−5,7)≡(x1,y1)Q(−4,−5)≡(x2,y2)R(4,5)≡(x3,y3)To find :- Area of triangle PQRSolution :-Ref. imageP(x1,y1),Q(x2,y2),R(x3,y3) are vertices of a triangle

AnswerGiven data :- P(−5,7)≡(x1,y1)Q(−4,−5)≡(x2,y2)R(4,5)≡(x3,y3)To find :- Area of triangle PQRSolution :-Ref. imageP(x1,y1),Q(x2,y2),R(x3,y3) are vertices of a trianglear(△PQR)=21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]

AnswerGiven data :- P(−5,7)≡(x1,y1)Q(−4,−5)≡(x2,y2)R(4,5)≡(x3,y3)To find :- Area of triangle PQRSolution :-Ref. imageP(x1,y1),Q(x2,y2),R(x3,y3) are vertices of a trianglear(△PQR)=21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]=21[−5(−5−5)−4(5−7)+4(7+5)]

AnswerGiven data :- P(−5,7)≡(x1,y1)Q(−4,−5)≡(x2,y2)R(4,5)≡(x3,y3)To find :- Area of triangle PQRSolution :-Ref. imageP(x1,y1),Q(x2,y2),R(x3,y3) are vertices of a trianglear(△PQR)=21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]=21[−5(−5−5)−4(5−7)+4(7+5)]=21[50+8+48]

AnswerGiven data :- P(−5,7)≡(x1,y1)Q(−4,−5)≡(x2,y2)R(4,5)≡(x3,y3)To find :- Area of triangle PQRSolution :-Ref. imageP(x1,y1),Q(x2,y2),R(x3,y3) are vertices of a trianglear(△PQR)=21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]=21[−5(−5−5)−4(5−7)+4(7+5)]=21[50+8+48]=

Answer 2

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