Question

find the area of
the triangle formed by the straight line
3x-4y+12=0
with coordinate axes
​

Answer 1

Answer:

Given straight line equation is 3x – 4y + 12 = 0 ––––– (1)

⇒ 3x – 4y = –12.

⇒ (3x/-12) - (4y/-12) = 1.

⇒ (x/-4) + (y/3) = 1.

X – intercept = – 4.

Y – intercept = 3.

Area of the triangle formed by the straight line (1) with the.

co-ordinate axes is (1/2) |(X – intercept) (Y – intercept)|