Question

Find the area of the triangle formed by the tips of the vectors a = i – j -3k, b= 4i-3j+k and c = 3ij+2k.

Answer 1

Answer:

We know that in a parallelogram when the two adjacent sides are given by \vec {AB}

AB

and \vec {AC}

AC

and the angle between the two sides are given by θ then the area of the parallelogram will be given by |\vec {AB} \times \vec {AC}|∣

AB

×

AC

∣ and the value will be given by |\vec {AB} | \times |\vec {AC}|∣

AB

∣×∣

AC

∣× sin⁡ θ.

A triangle divides a parallelogram into two equal parts, so the area of the triangle will be given by 1/2 x |\vec {AB} | \times |\vec {AC}|∣

AB

∣×∣

AC

∣× sin⁡θ

Explanation:

Ok