Question

Find the area of the triangle having perimeter is 32cm.one side of its side is equal to 11cm and difference of the other two is 5cm

Answer 1

let length of three sides of triangles is a, b, c
preimeter is 32
a+b+c=32
let a=11
b+c=21
given b-c=5
2b=26
b=13
2c=16
c=8
sides a=11, b=13,c=8
area =root of(s(s-a)(s-b)(s-c)
s=a+b+c/2
  =32/2=16
area = root of(s(s-a)(s-b)(s-c)
         =root of(16(5)(3)(8))
           =8(root of(30))