Question

find the area of the triangle having three sides as 4;6;and 8 cm

Answer 1

$\textbf{\huge{ANSWER:}}$

$\sf{Given:}$

Sides of a triangle = 4 cm, 6 cm, 8 cm

$\sf{To\:find:}$

The Area of the triangle

$\sf{Solution:}$

By Heron's Formula:

$\sqrt{s (s - a) (s - b) (s - c)}$

Where, a , b , and c are the sides of a triangle and s = Semiperimeter.

s = $\frac{Perimeter}{2}$
=》 s = 9 cm

Apply the Heron's Formula:

$\sqrt{9 (9 - 4) (9 - 6) (9 - 8)}$
=》 $3\sqrt{ 5\times 3}$
=》 $3\sqrt{15}cm^{2}$

Hope it Helps!! :)

Answer 2

${\boxed {\boxed {\boxed {\sf{Here's \: the \: answer}}}}}$

Given =>

Three sides are 4 , 6 , 8 cm respectively.

To find =>

Area of the triangle = ?

Solution -

Using Heron's Formula -

$\sf{s = \frac{a + b + c}{2}}$

$\sf{s = \frac{4 + 6 + 8}{2}}$

$\sf{s = \frac{18}{2}}$

$\sf{s = 9 \: cm}$

Now,

$\sf{ \sqrt{s(s - a) (s - b) (s - c)}}$

$\sf{ = \sqrt{9(9 - 4)(9 - 6)(9 - 8)}}$

$\sf{= \sqrt{9 \times 5 \times 3 \times 1}}$

$\sf{= 3 \sqrt{15}}$


Thus,

The area of the triangle is 3 √15 sq. cm

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Thanks!