find the area of the triangle if its sides are 56cm,60cm and 52cm.
Answers
Answered by
5
Answer:
1344 cm^2
Step-by-step explanation:
According to the question,
Sides of a triangle,
a = 56, b = 60, c = 52
s = (a + b + c)/2
⇒ s = (56 + 60 + 52)/2
= 168/2 = 84
Area of triangle = √s(s-a)(s-b)(s-c)
= √84(84-56)(84-60)(84-52)
= √84×28×24×32
= 1344cm^2
Answered by
1
Answer:
672 cm square
Step-by-step explanation:
a = 56cm b = 60cm c = 52cm
semiperimeter s = a+b+c/2
= 56+60+52/2
= 168/2 = 84 cm
s-a = 84 - 56 = 28
s-b = 84 - 60 = 24
s-c = 84 - 52 = 32
area = √s(s-a)(s-b)(s-c)
= √84 × 28 × 24 × 32
= √14 × 2 × 3 × 14 ×2 × 8 × 3 × 8 × 4
= 14 × 8 × 2 × 3 ×2{remove root}
= 672
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