Question

Find the area of the triangle in square cm whose base is 47 cm and altitude is 31 dm​

Answer 1

HELLOW FRIEND,

AREA OF TRIANGLE

$\frac{1}{2} \times base \times height$

1 dm = 10 cm

Therefore,

31 dm = 31× 10

= 310 cm

Area

$= > \frac{1}{2} \times 47 \times 310 \\ = > 7285 \: {cm}^{2}$

THIS IMPLIES THAT THE AREA OF THE RECTANGLE IS 7,285 CM^2.

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