Question

find the area of the triangle in which a=13m,b=14m,c=15m​

Answer 1

semi perimeter (s) =(13+14+15)/2=42/2=21 m,

then

Area of the ∆=√[21(21-13)(21-14)(21-15)],

=√[21×8×7×6],

=√(3×7×2×2×2×7×2×3),

=3×7×2×2,

=84 m²

Answer 2

Answer:

area = √ s(s-a)(s-b)(s-c)

s=a+b+c÷2

=√21(21-13)(21-14)(21-15)

=√21×336

=√7056

=84