Question

Find the area of the triangle in which a=52cm,b=56cm,c=60cm

Answer 1

sides of the triangle are a- 52cm, b-56cm, c- 60cm.

semi perimeter= (a+b+c)/2
=(52+56+60)/2= 84cm

by herons formula=√s(s-a)(s-b)(s-c)
=√84(84-52)(84-56)(84-60)
=√84×32×28×24
= 2×3×7×2×2×2×2×2
=1344cm sq

PLZ LET ME KNOW IF I AM WRONG...

Answer 2

Answer:

$1344cm^2$

Step-by-step explanation:

Sides of triangle

a = 52 cm

b = 56 cm

c = 60 cm

To find the area of triangle we will use Heron's Formula:

$A=\sqrt{s(s-a)(s-b)(s-c)}$

where $s=\frac{a+b+c}{2}$

Substitute the values :

$s=\frac{52+56+60}{2}$

$s=84$

$A=\sqrt{84(84-52)(84-56)(84-60)}$

$A=1344cm^2$

Hence the area of triangle is $1344cm^2$