Math, asked by ratna77, 1 year ago

find the area of the triangle in which each of the equal sides measure 30 CM and the third side is 48 CM. ​

Answers

Answered by savitasangalad
0

Answer:

Step-by-step explanation:use area of a triangle formula

Half*base*height

1/2*30*48

Cancel 2 and 48

So,1*30*24

So the area of the triangle is 720cm^2

The triangle is an isosceles triangle

Answered by vidushimishra7d
0

Step-by-step explanation:

Area of the triangle=1/2*b*h

                                =1/2*30*48

        Cut 2 with48   =30*24

                                 =720

        Divide720 by2= 720/2

 Area of the triangle= 360cm square

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