Find the area of the triangle sides are 9 12 &115 cm with procedure
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Area of triangle,A=√s(s-a) (s-b) (s-c)
where S=a+b+c/2. (half of perimeter)
a=9 cm
b=12 cm
c=115 cm
S=9+12+115/2
S=136/2=68
s-a=68-9=59
s-b=68-12=56
s-c=68-115= –ve value
the triangle is not possible as one of it's side is negative. Moreover,
the sum of two sides is not greater than the third side.
115+12 > 9
it is not correct
so,area of triangle is not possible as the triangle formation is not possible
where S=a+b+c/2. (half of perimeter)
a=9 cm
b=12 cm
c=115 cm
S=9+12+115/2
S=136/2=68
s-a=68-9=59
s-b=68-12=56
s-c=68-115= –ve value
the triangle is not possible as one of it's side is negative. Moreover,
the sum of two sides is not greater than the third side.
115+12 > 9
it is not correct
so,area of triangle is not possible as the triangle formation is not possible
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