Question

Find the area of the triangle two sides of which are 8 cm and 11cm and the perimeter is 32 CM

Answer 1

Answer:

given,

peimeter=32 cm.

sides=8,11

=sum of both sides - perimetre

32-8+11

32-19=13

sides=8 cm., 11 cm., 13 cm.

semi perimeter =a+ b+ c / 2

= 8+11+13 /2

32/2

so, s=16 cm.

area of a triangle = [root under] s(s-a) (s-b) (s-c)

s-a=16-8=8

s-b=16-11=5

s-c=16-13=3

[root under] 16 x 8 x 5 x 3

[root under] 2 x 8 x 8 x 5 x 3

=8 [root under] 30

Answer 2

area of triangle = 1/2×b×h
1/2×8×11
1×4×11=44cm sq