Question

Find the area of the triangle which sides are35cm,54cm,61cm.

Answer 1

Hey mate!!

Sides of ∆ are

a = 35 cm
b = 54 cm
c = 61 cm

✴HERON'S FORMULA✴

s = a+b+c/2

s = 35 + 54 +61/2

s = 150/2

s = 75

$\bold{area \: of \triangle} = \\ \\ \bold{ \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ \sqrt{75(75 - 35)(75 - 54)(75 - 61) } \\ \\ \sqrt{75 \times 40 \times 21 \times 14} \\ \\ \sqrt{5 \times 5 \times 3 \times 5 \times 4 \times 2 \times 3 \times 7 \times 2 \times 7 \times 3} \\ \\ 5 \times 3 \times 2 \times 2 \times 7 \sqrt{5} \\ \\ 420 \sqrt{5}$

Thanks for the question!!

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