Question

Find the area of the triangle whoose vertices taken in order are ((-4'2)' (-3'-5)' (3'-2)

Answer 1

The area of triangle is "24 square units".

Step-by-step explanation:

Here, $x_1 = - 4, y_1 = 2, x_2 =-3, y_2 = - 5$and $x_3 = 3, y_3 = -2.$

We know that,

Area of triangle

= $\dfrac{1}{2}$ × ${x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)}$

∴ Area of triangle ABC

= $\dfrac{1}{2}$ × {(- 4)( - 5 + 2) - 3(- 2 - 2) + 3(2 + 5)}

= $\dfrac{1}{2}$ × {12 + 15 + 21}

= $\dfrac{1}{2}$ × 48

= 24 square units

Hence, the area of triangle is "24 square units".

Answer 2

Answer:

your question is wrong it must be 25

Step-by-step explanation: