find the area of the triangle whose all three medians are 12
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Answered by
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Hii friend,.
M1 = 12, M2 = 12 , M3 = 12
THEREFORE,
Sm = 1/2(M1+M2+M3)
Sm = 1/2×(12+12+12)
Sm = 1/2× 36 = 18 .
S-M1 = S-M2 = S-M3 = 18-12 = 6
THEREFORE,
Area of the triangle = 4/3×✓Sm(S-M1)(S-M2)(S-M3) .
PUT VALUES AND SOLVE... U WILL GET THE AREA OF TRIANGLE....
M1 = 12, M2 = 12 , M3 = 12
THEREFORE,
Sm = 1/2(M1+M2+M3)
Sm = 1/2×(12+12+12)
Sm = 1/2× 36 = 18 .
S-M1 = S-M2 = S-M3 = 18-12 = 6
THEREFORE,
Area of the triangle = 4/3×✓Sm(S-M1)(S-M2)(S-M3) .
PUT VALUES AND SOLVE... U WILL GET THE AREA OF TRIANGLE....
Rhidam:
Hii
Answered by
0
I think 392 cm!!!!!!!!! hope it helps you
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