Find the area of the triangle whose base and altitude are 3+√3and 3-√3
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Area of Triangle is 1/2*base *height
.˙.
=1/2*(3+√3)*(3-√3)
=1/2*3²-(√3)²
=1/2*9-3
=1/2*6
=3
.˙.
=1/2*(3+√3)*(3-√3)
=1/2*3²-(√3)²
=1/2*9-3
=1/2*6
=3
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