Find the area of the triangle whose base and altitude are 3+√3and 3-√3
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We know that
Area of Triangle = 1/2(height) (base)
=> 1/2(3- √3)(3+√3)
= > 1\2 [(3)^2 -(√3)^2]
=> 1\2( 9-3)
=> 1\2(6)
=> 3
Therefore the area of the triangle is 3sq.units
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Area of Triangle = 1/2(height) (base)
=> 1/2(3- √3)(3+√3)
= > 1\2 [(3)^2 -(√3)^2]
=> 1\2( 9-3)
=> 1\2(6)
=> 3
Therefore the area of the triangle is 3sq.units
PLS MARK ME AS THE BRAINLIEST ANSWER
I WANT ACHIEVE THAT VIRTUOSO RANK VERY MUCH....
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