Question

find the area of the triangle whose base and attitude are
$3 + \sqrt{3}$
and
$3 - \sqrt{3}$
​

Answer 1

Answer:

area of triangle is 1/2×base × height

therefore area

=1/2×[√3+3]×[√3-3]

this is ur answer

hope it helps

Answer 2

Answer:

Hola‼.....✌

Your answer is in the attachment.