Question

find the area of the triangle whose base is b and height is twice it's base​

Answer 1

Hey there!!!!! here is your answer

Answer:

b^2

Step-by-step explanation:

Let the base be (b)

Let the height be (2b)

Area of the triangle=1/2×b×h

=1/2×b×2b

=1/2×2b^2

=b^2

Therefore, the area of the triangle is b^2.

Hope it helps you!!!

Answer 2

Answer:

Hence, area of triangle will be  $=b^2\:Sq.\:unit$

Step-by-step explanation:

In context to question asked,

We have to determine the area of triangle.

As per data given in the question,

We have,

Base of triangle = b units

Height of triangle = twice of base = 2b units

As we know that,

Triangle is a three sided figure,

Sum of all angles of the triangle is 180 degree.

The area of triangle can be determined by using formula $Area = \frac{1}{2} \times base \times Height$

So, for determining the area of triangle we will put the value of base and height given in the question in above formula,

Thus we will get it as,

$Area =\frac{1}{2} \times b \times 2b\\=>Area = b \times b\\=>Area =b^2 \:unit^2$