Question

find the area of the triangle whose lenghts of sides are 15cm,17cm,21cm(useheron's formula)​

Answer 1

Answer :-

➤ Area of triangle= 24.51$cm {}^{2}$

Step By Step Explanation :-

Given:-

• a = 15cm
• b = 17cm
• c = 21cm

S = a+b+c/2

= 15+17+21/2

= 53/2

S = 26.5cm

➤ Heron's formula = $\sqrt{(s - a)(s -b)(s-c)}$

➜ Area of triangle= $\sqrt{(26.5-15)(26.5-17)(26.5-21)}$

➜ Area of triangle = $\sqrt{ 11.5× 9.5 × 5.5}$

➜ Area of triangle = $\sqrt{600.875}$

➜ Area of triangle = 24.51$cm {}^{2}$

Hope it will help uh!!