Math, asked by prativakalita9999, 10 months ago

find the area of the triangle whose length is 1 and 2 and 3 using herons feirmula
 \sqrt{(s)(s - a)(s - b)(s - c)}

Answers

Answered by saivivek16
6

Step-by-step explanation:

Aloha !

Δ=√s(s-a) (s-b) (s-c)

s=a+b+c/2

s=1+2+3/2

s=6/2

s=3

Δ=√3(3-1)(3-2)(3-3)

Δ=√3(2)(1)(0)

Δ=0

Hope it will help you

@ Sweety Adihya

Answered by SwaggerGabru
4

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