find the area of the triangle whose length is 1 and 2 and 3 using herons feirmula
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Step-by-step explanation:
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Δ=√s(s-a) (s-b) (s-c)
s=a+b+c/2
s=1+2+3/2
s=6/2
s=3
Δ=√3(3-1)(3-2)(3-3)
Δ=√3(2)(1)(0)
Δ=0
Hope it will help you
@ Sweety Adihya
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