Question

Find the area of the triangle whose perimeter is 270cm and the ratio of the sides are 25 : 17 : 12​

Answer 1

Answer:

2250 cm²

Step-by-step explanation:

let sides of triangle be 25x, 17x, 12x

perimeter = 25x+17x+12x=54x=270

x=5

so sides of triangle would be a=125 cm², b=85cm² and c=60cm²

now apply heron's formula for calculation of area

s (semi perimeter) = 135 cm

$Area = \sqrt{s(s-a)(s-b)(s-c)}\\\\Area = \sqrt{135 (135-125) (135-85)(135-60)}$

Area = $\sqrt{135*10*50*75}$

Area= 2250 cm²

Answer 2

Answer:

Step-by-step explanation:

area of triangle=√s(s-a) (s-b) (s-c)

here ,s is the semi-perimeter,

and,a,b,c, are the sides of triangle

given perimeter=270cm

semi-perimeter=s=perimeter/2

                           s=270/2

                           s=135cm

given ratios of sides is25:17:12

let sides be a=25x , b=17x , c=12x

where x is any no.

now,

perimeter = 270cm

a+b+c = 270cm

25x + 17x + 12x =270cm

42x + 12x =270cm

54x = 270cm

x = 270/54

x=5cm

so , ax=25x = 25*5 = 125cm

      bx=17x = 17*5 = 85cm

     cx=12x = 12*5 = 60cm

Area of triangle can be calculated by heron/s formula

which comes to 2250m squared