Find the area of the triangle whose primeter is 24 and two sides are two sides are 6 and 8
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Answered by
2
Answer:
Let a=?
b=6
c=8
Perimeter = a+b+c
24=a+6+8
24-14=a
a=10
s=a+b+c/2
s=24/2
s=12
area of= under root s(s-a) (s-b) (s-c)
=under root 12(12-10)(12-6)(12-8)
=under root 12(2) (6) (4)
=under root 3*2*2*2*2*3*2*2
=2*2*2*3
=24cm^2
Step-by-step explanation:
ANSWER IS 24cm^2
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1
Answer:
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