Question

find the area of the triangle whose side are 13cm,14 cm and 15 CM

Answer 1

By using herons formula
We get s=13+14+15/2
S=21cm
Now area=√s(s-a) (s-b) (s-c)
√21(21-13)(21-14)(21-15)
√21(8)(7)(6)
√21(336)
√7056
84 cm² is the area

Answer 2

Answer:

84 sq.m.

Step-by-step explanation:

Given : Sides of triangle are 13 cm,14 cm and 15 CM

To Find :find the area of the triangle

Solution:

We will use heron's formula :

$A=\sqrt{s(s-a)(s-b)(s-c)}$

Where $s=\frac{a+b+c}{2}$

a = 13

b = 14

c = 15

$s=\frac{13+14+15}{2}$

$s=21$

$A=\sqrt{21(21-13)(21-14)(21-15)}$

$A=84$

Hence the area of the triangle is 84 sq.m.